Besoin d'aide svp Résoudre les deux systèmes: {2x + 3y = 5 {3x - 2y = 7 {2x+ 4y = 5 {x+ 2y = 7

Sytème 1 :

[tex] \left \{ {{2x+3y=5} \atop {3x-2y=7}} \right\\\\ \left \{ {{6x+9y=15} \atop {6x-4y=14}} \right \\\\ 6x-6x+9y-(-4y)=15-14\\ 13y=1\\ y = \frac{1}{13} \\\\ x= \frac{5-3\times \frac{1}{13} }{2}= \frac{31}{13} \\\\ \boxed{ \left \{ {{x= \frac{31}{13} } \atop {y= \frac{1}{13} }} \right. } [/tex]

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Système 2 : 

[tex] \left \{ {{2x+4y=5} \atop {x+2y=7}} \right. \\\\ \left \{ {{2x+4y=5} \atop {2x+4y=14}} \right. \\\\ 2x-2x+4y-4y=5-14\\ 0=-9 \ \ \ => impossible\\\\ \boxed{\text{Le systeme n'admet aucune solution}}[/tex]