F(x) = -12x² +48+ 12/3 1 . Mettre sous la forme canonique . Mercii de bien vouloir m'aider .

[tex]f(x) = -12x^2+48x+ \frac{12}{3}\\\\ f(x) = a(x-\alpha)^2+\beta\\\\ \alpha = \frac{-48}{2\times(-12)}= 2\\\\ \beta = f(\alpha)=f(2) = -12\times2^2+12\times2+ \frac{12}{3} =52\\\\ \boxed{f(x) = -12(x-2)^2+52}[/tex]