Mathématiques

Question

Factorise:

du g au j
merci d’avance
Factorise: du g au j merci d’avance

1 Réponse

  • Bonjour,

    G = 3(2 + 3x) - (3x - 7)(2 + 3x)

    G = (2 + 3x)[(3 - (3x - 7)]

    G = (2 + 3x)(3 - 3x + 7)

    G = (2 + 3x)(-3x + 10)

    H = (5x - 4)(2x + 1) - (5x - 4)(4x - 3)

    H = (5x - 4)[(2x + 1) - (4x - 3)]

    H = (5x - 4)(2x + 1 - 4x + 3)

    H = (5x - 4)(-2x + 4)

    J = (1 + 6x)²- (1 + 6x)(2 - 5x)

    J = (1 + 6x)[(1 + 6x) - (2 - 5x)]

    J = (1 + 6x)(1 + 6x - 2 + 5x)

    J = (1 + 6x)(x - 1)