[tex] \sqrt{x} \sqrt{x} \sqrt{x} \sqrt{x} [/tex]Aidez moi svp [tex] \frac{7x-12}{-5} [/tex] [tex] \geq [/tex] 6 & [tex] \sqrt{10} \sqrt{5} + 3 \sqrt{18} - 2

[tex] \frac{7x-12}{-5} \geq 6\\\\ 7x-12 \leq -30\\\\ 7x \leq -18\\\\ x \leq \frac{-18}{7} [/tex]

[tex] \sqrt{10} \sqrt{5}+3 \sqrt{18}-2 \sqrt{98} = \sqrt{10\times5}+3 \sqrt{9\times2}-2 \sqrt{49\times2} \\\\ \sqrt{10} \sqrt{5}+3 \sqrt{18}-2 \sqrt{98} = \sqrt{25\times2} + 3 \sqrt{9\times2}-2 \sqrt{49\times2} \\\\ \sqrt{10} \sqrt{5}+3 \sqrt{18}-2 \sqrt{98} = \sqrt{25}\times \sqrt{2}+3 \sqrt{9}\times \sqrt{2}-2 \sqrt{49}\times \sqrt{2} } \\\\ \sqrt{10} \sqrt{5}+3 \sqrt{18}-2 \sqrt{98} = 5 \sqrt{2}+9 \sqrt{2} -14 \sqrt{2}\\\\ \sqrt{10} \sqrt{5}+3 \sqrt{18}-2 \sqrt{98} = 0[/tex]